WAEC Further Mathematics 2009 Question 24

Question 24

Indices and Logarithms

Simplify 2log38 − 3log32.

  1. A.−log34
  2. B.−log32
  3. C.3log32
  4. D.3log34
Show the answer and explanation

Answer: C (3log32)

Explanation

2log38 = log364 and 3log32 = log38. log3(64/8) = log38 = 3log32.