Question 9
Equilibrium of ForcesA uniform metre rule of weight 1.0N is pivoted at the 40cm. A weight of 2.0N is hung at the 15cm mark. Where must a weight of 2N be placed to balance the rule?
- A.60cm
- B.45cm
- C.55cm
- D.35cm
Show the answer and explanation
Answer: A (60cm)
Explanation
Anticlockwise moment: 2 × (40 − 15) = 50. Clockwise: 1 × (50 − 40) + 2 × (x − 40) = 50, so 2(x − 40) = 40 and x = 60 cm.