Question 22
Triangles and QuadrilateralsIn the figure below |PQ| = |PR| = |PS| and SR̂T = 68°, find QP̂S

- A.68°
- B.112°
- C.136°
- D.56°
Show the answer and explanation
Answer: C (136°)
Explanation
Triangles PQR and PRS are isosceles, so ∠PRQ = ∠PQR and ∠PRS = ∠PSR. On the straight line at R, ∠PRQ + ∠PRS = 180° − 68° = 112°. Then ∠QPS = (180° − 2∠PRQ) + (180° − 2∠PRS) = 360° − 224° = 136°.