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JAMB Physics 2014 Question 26

Question 26

Waves

The distance between two successive crests of a wave is 15 cm and the velocity 300 ms−1. Calculate the frequency.

  1. A.4.5 × 105Hz.
  2. B.2.0 × 103Hz.
  3. C.4.5 × 102Hz.
  4. D.2.0 × 102Hz.
Show the answer and explanation

Answer: B (2.0 × 103Hz.)

Explanation

The wavelength is 0.15 m. f = v/λ = 300 ÷ 0.15 = 2000 Hz = 2.0 × 103 Hz.