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JAMB Physics 2013 Question 36

Question 36

Electrostatics

Calculate the force acting on an electron of charge 1.5 × 10−19C placed in an electric field of intensity 105Vm−1.

  1. A.1.5 × 10−11N.
  2. B.1.5 × 10−12N.
  3. C.1.5 × 10−13N.
  4. D.1.5 × 10−14N.
Show the answer and explanation

Answer: D (1.5 × 10−14N.)

Explanation

F = qE = 1.5 × 10−19 × 105 = 1.5 × 10−14 N.