Question 18
Gas LawsA gas at a pressure of 105Nm−2 expands from 0.6m3 to 1.2m3 at constant temperature, the work done is
- A.7.0 × 106J.
- B.6.0 × 106J.
- C.6.0 × 105J.
- D.6.0 × 104J.
Show the answer and explanation
Answer: D (6.0 × 104J.)
Explanation
Taking the pressure as constant, work done = pΔV = 105 × (1.2 − 0.6) = 6.0 × 104 J.