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JAMB Physics 2013 Question 14

Question 14

Pressure

At what depth below the sea-level would one experience a change of pressure equal to one atmosphere? [Density of sea water = 1013kgm−3 one atmosphere = 1.01 × 105Nm−2 g = 10ms−2]

  1. A.0.1m.
  2. B.1.0m.
  3. C.10.0m.
  4. D.100.0m.
Show the answer and explanation

Answer: C (10.0m.)

Explanation

p = hρg, so h = p/(ρg) = 1.01 × 105 ÷ (1013 × 10) ≈ 10 m.