Question 34
CapacitorsThree capacitors of capacitance, 2μF, 4μF and 8μF are connected in parallel and a p.d of 6 V is maintained across each capacitor, the total energy stored is
- A.6.90 × 10−5 J.
- B.6.90 × 10−4 J.
- C.2.52 × 10−4 J.
- D.2.52 × 10−6 J.
Show the answer and explanation
Answer: C (2.52 × 10−4 J.)
Explanation
In parallel C = 2 + 4 + 8 = 14 μF. Energy = ½CV2 = ½ × 14 × 10−6 × 62 = 2.52 × 10−4 J.