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JAMB Physics 2010 Question 11

Question 11

Elasticity

If a wire 30 cm long is extended to 30.5 cm by a force 300 N. Find the strain energy of the wire.

  1. A.7.50 J.
  2. B.750.00 J.
  3. C.75.00 J.
  4. D.0.75 J.
Show the answer and explanation

Answer: D (0.75 J.)

Explanation

Extension = 0.5 cm = 0.005 m. Strain energy = ½Fe = ½ × 300 × 0.005 = 0.75 J.