JAMB Physics 2008 Question 46

Question 46

Radioactivity and Nuclear Physics

14N + 4He → 17O + X
In the equation above, the particle X is

  1. A.a proton.
  2. B.a neutron.
  3. C.an α − particle.
  4. D.a β − particle.
Show the answer and explanation

Answer: A (a proton.)

Explanation

Mass numbers: 14 + 4 = 17 + 1. Atomic numbers: 7 + 2 = 8 + 1. X has mass number 1 and atomic number 1, so it is a proton.