Question 13
FrictionA motorcycle of mass 100 kg moves round in a circle of radius 10 m with a velocity of 5ms−1. Find the coefficient of friction between the road and the tyres. [g=10ms−2]
- A.25.00
- B.2.50
- C.0.50
- D.0.25
Show the answer and explanation
Answer: D (0.25)
Explanation
Friction provides the centripetal force: μmg = mv2/r, so μ = v2/(rg) = 25 ÷ (10 × 10) = 0.25.