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JAMB Physics 2007 Question 34

Question 34

Density and Upthrust

A piece of iron weighs 250 N in air and 200 N in a liquid of density 1000 kgm−3. The volume of the iron is [g=10ms−2]

  1. A.2.0 × 10−3 m3.
  2. B.2.5 × 10−3 m3.
  3. C.4.5 × 10−3 m3.
  4. D.5.0 × 10−3 m3.
Show the answer and explanation

Answer: D (5.0 × 10−3 m3.)

Explanation

Upthrust = 250 − 200 = 50 N = ρVg, so V = 50 ÷ (1000 × 10) = 5.0 × 10−3 m3.