Question 27
ElectrostaticsIf two charged plates are maintained at a potential difference of 3 kV, the work done in taking a charge of 600 μC across the field is
- A.9.0 J.
- B.0.8 J.
- C.18.0 J.
- D.1.8 J.
Show the answer and explanation
Answer: D (1.8 J.)
Explanation
W = QV = 600 × 10−6 × 3000 = 1.8 J.