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JAMB Physics 2006 Question 8

Question 8

Modern Physics

The energy associated with the emitted photon when a mercury atom changes from one state to another is 3.3 eV. Calculate the frequency of the photon. [e = 1.6 × 10−19 C; h = 6.6 × 10−34 Js]

  1. A.8.0 × 1014 Hz
  2. B.3.1 × 1052 Hz
  3. C.1.3 × 10−15 Hz
  4. D.3.2 × 10−53 Hz
Show the answer and explanation

Answer: A (8.0 × 1014 Hz)

Explanation

E = 3.3 × 1.6 × 10−19 = 5.28 × 10−19 J. f = E/h = 5.28 × 10−19 ÷ 6.6 × 10−34 = 8.0 × 1014 Hz.