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JAMB Physics 2004 Question 50

Question 50

Capacitors

Given three capacitors 0.3μF, 0.5μF and 0.2μF, the joint capacitance when arranged to give minimum capacitance is

  1. A.0.3μF.
  2. B.1.0μF.
  3. C.0.1μF.
  4. D.0.5μF.
Show the answer and explanation

Answer: C (0.1μF.)

Explanation

Minimum capacitance is in series: 1/C = 1/0.3 + 1/0.5 + 1/0.2 ≈ 10.3, so C ≈ 0.1 μF.