Question 35
ElasticityIf a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?
- A.100N
- B.50N
- C.250N
- D.200N
Show the answer and explanation
Answer: C (250N)
Explanation
By Hooke's law force ∝ extension: 0.05 m is 5 times 0.01 m, so F = 5 × 50 = 250 N.