Question 45
Alternating Current CircuitsWhen an alternating current given by I = 10sin(120π)t passes through a 12Ω resistor, the power dissipated in the resistor is
- A.1200W
- B.600W
- C.120W
- D.30W
Show the answer and explanation
Answer: B (600W)
Explanation
Irms = 10/√2 A, so P = Irms2R = 50 × 12 = 600 W.