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JAMB Physics 2003 Question 33

Question 33

Electrostatics

An electron of charge 1.6 × 10−19C is accelerated between two metal plates. If the kinetic energy of the electron is 4.8 × 10−17J, the potential difference between the plates is

  1. A.30V
  2. B.40V
  3. C.300V
  4. D.400V
Show the answer and explanation

Answer: C (300V)

Explanation

eV = KE, so V = 4.8 × 10−17 ÷ 1.6 × 10−19 = 300 V.