passwella.
Menu

JAMB Physics 2003 Question 31

Question 31

Refraction of Light

A ray of light is incident on an equilateral triangular glass prism of refractive index 3/2. Calculate the angle through which the ray is minimally deviated in the prism.

  1. A.30.0°
  2. B.37.2°
  3. C.42.0°
  4. D.48.6°
Show the answer and explanation

Answer: B (37.2°)

Explanation

n = sin((A + D)/2) ÷ sin(A/2). With A = 60° and n = 1.5: sin((60 + D)/2) = 0.75, so (60 + D)/2 = 48.6° and D ≈ 37.2°.