Question 26
Heat TransferIf 1.2 × 106J of heat energy is given off in 1 sec. from a vessel maintained at a temperature gradient of 30Km−1, the surface area of the vessel is [thermal conductivity of the vessel = 400Wm−1K−1]
- A.1.0 × 102m2
- B.9.0 × 102m2
- C.1.0 × 103m2
- D.9.0 × 104m2
Show the answer and explanation
Answer: A (1.0 × 102m2)
Explanation
Q/t = kA × (temperature gradient), so A = 1.2 × 106 ÷ (400 × 30) = 100 m2.