Question 1
FrictionA bead travelling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1, determine the work done by the friction. [g = 10ms−2]
- A.2 × 10−4J
- B.2 × 10−3J
- C.2 × 101J
- D.2 × 102 J
Show the answer and explanation
Answer: B (2 × 10−3J)
Explanation
Friction = μmg = 0.1 × 0.01 × 10 = 0.01 N; work = 0.01 × 0.2 = 2 × 10−3 J.