JAMB Physics 2002 Question 49

Question 49

Radioactivity and Nuclear Physics

2311Na + X → 209F + 42He
What particle is X in the reaction above?

  1. A.Beta
  2. B.Gamma
  3. C.Alpha
  4. D.Neutron
Show the answer and explanation

Answer: D (Neutron)

Explanation

Mass numbers: 23 + A = 20 + 4 gives A = 1. Atomic numbers: 11 + Z = 9 + 2 gives Z = 0. A particle with mass 1 and charge 0 is a neutron.