Question 30
CapacitorsThe energy stored in a capacitor of capacitance 10μF carrying a charge of 100μC is
- A.4 × 10−3J
- B.5 × 10−4J
- C.5 × 10−1J
- D.4 × 10−2J
Show the answer and explanation
Answer: B (5 × 10−4J)
Explanation
E = Q2/(2C) = (100 × 10−6)2 ÷ (2 × 10 × 10−6) = 5 × 10−4 J.