Question 18
Gas LawsThe pressure of 3 moles of an ideal gas at a temperature of 27°C having a volume of 10−3m3 is [R = 8.3 J mol−1 K−1]
- A.2.49 × 106Nm−2
- B.7.47 × 106 Nm−2
- C.2.49 × 105 Nm−2
- D.7.47 × 105Nm−2
Show the answer and explanation
Answer: B (7.47 × 106 Nm−2)
Explanation
P = nRT/V = 3 × 8.3 × 300 ÷ 10−3 = 7.47 × 106 N m−2.