Question 38
Alternating Current CircuitsIn the diagram above, determine the r.m.s. current

- A.31 A
- B.48 A
- C.60 A
- D.80 A
Show the answer and explanation
Answer: B (48 A)
Explanation
Impedance Z = √(42 + 32) = 5 Ω, so Irms = 240/5 = 48 A.
In the diagram above, determine the r.m.s. current

Answer: B (48 A)
Impedance Z = √(42 + 32) = 5 Ω, so Irms = 240/5 = 48 A.