Question 36
Current ElectricityA cell can supply currents of 0.4 A and 0.2 A through a 4.0 Ω and 10.0 Ω resistors respectively. The internal resistance of the cell is
- A.2.0 Ω
- B.1.0 Ω
- C.2.5 Ω
- D.1.5 Ω
Show the answer and explanation
Answer: A (2.0 Ω)
Explanation
E = 0.4(4 + r) = 0.2(10 + r), so 1.6 + 0.4r = 2 + 0.2r, giving 0.2r = 0.4 and r = 2.0 Ω.