Question 5
Simple Harmonic MotionA simple pendulum has a period of 17.0 s. When the length is shortened by 1.5 m, its period is 8.5 s. Calculate the original length of the pendulum.
- A.1.5 m
- B.2.0 m
- C.3.0 m
- D.4.0 m
Show the answer and explanation
Answer: B (2.0 m)
Explanation
T ∝ √L, so (17/8.5)2 = L/(L − 1.5), i.e. 4 = L/(L − 1.5). Then 4L − 6 = L and L = 2.0 m.