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JAMB Physics 2000 Question 49

Question 49

Electromagnetic Induction

An electric generator with a power output of 3.0 kW at a voltage of 1.5 kV distributes power along cables of total resistance 20.0 Ω. The power loss in the cable is

  1. A.0.1 W
  2. B.10.0 W
  3. C.40.0 W
  4. D.80.0 W
Show the answer and explanation

Answer: D (80.0 W)

Explanation

I = P/V = 3000/1500 = 2 A. Power lost = I2R = 22 × 20 = 80.0 W.