Question 40
Current ElectricityA cell of internal resistance 1 Ω supplies current to an external resistor of 3 Ω. The efficiency of the cell is
- A.75%
- B.50%
- C.33%
- D.25%
Show the answer and explanation
Answer: A (75%)
Explanation
Efficiency = useful power/total power = R/(R + r) = 3/(3 + 1) = 75%.