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JAMB Physics 2000 Question 23

Question 23

Waves

A travelling wave moving from left to right has an amplitude of 0.15 m, a frequency of 550 Hz and a wavelength of 0.01 m. The equation describing the wave is

  1. A.y = 0.15 sin 200π (x − 5.5t)
  2. B.y = 0.15 sin π(0.01x − 5.5t)
  3. C.y = 0.15 sin 5.5π(x − 200t)
  4. D.y = 0.15 sin π(550x − 0.01t)
Show the answer and explanation

Answer: A (y = 0.15 sin 200π (x − 5.5t))

Explanation

k = 2π/λ = 2π/0.01 = 200π and ω = 2πf = 1100π = 200π × 5.5. So y = 0.15 sin(200πx − 1100πt) = 0.15 sin 200π(x − 5.5t).