Question 47
Modern PhysicsWhat is the speed of a particle of mass 10−27 kg whose wavelength is 10−8 m? [h = 6.63 × 10−34 J s]
- A.6.63 m s−1
- B.66.30 m s−1
- C.663.00 m s−1
- D.6630.00 m s−1
Show the answer and explanation
Answer: B (66.30 m s−1)
Explanation
de Broglie: λ = h/(mv), so v = h/(mλ) = 6.63 × 10−34/(10−27 × 10−8) = 66.3 m s−1.