Question 38
CapacitorsIn the circuit above, the potential across each capacitor is 100 V. The total energy stored in the two capacitors is
- A.3.0 × 104 J
- B.3.0 × 102 J
- C.2.5 × 10−2 J
- D.6.0 × 10−3 J.
Show the answer and explanation
Answer: C (2.5 × 10−2 J)
Explanation
The 2 μF and 3 μF capacitors are in parallel: C = 5 μF. Energy = ½CV2 = ½ × 5 × 10−6 × 1002 = 2.5 × 10−2 J.