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JAMB Physics 1999 Question 26

Question 26

Heat Transfer

The temperature gradient across a copper rod of thickness 0.02 m, maintained at two temperature junctions of 20 °C and 80 °C respectively is

  1. A.3.0 × 102 K m−1
  2. B.3.0 × 103 K m−1
  3. C.5.0 × 103 K m−1
  4. D.3.0 × 104 K m−1
Show the answer and explanation

Answer: B (3.0 × 103 K m−1)

Explanation

Temperature gradient = temperature difference ÷ thickness = (80 − 20)/0.02 = 3000 = 3.0 × 103 K m−1.