Question 24
Change of State and VapoursCalculate the mass of ice that would melt when 2 kg of copper is quickly transferred from boiling water to a block of ice without heat loss [Specific heat capacity of copper = 400 J kg−1 K−1; Latent heat of fusion of ice = 3.3 × 105 J kg−1]
- A.8/33 kg
- B.33/80 kg
- C.80/33 kg
- D.33/8 kg
Show the answer and explanation
Answer: A (8/33 kg)
Explanation
Heat given by copper cooling from 100 °C to 0 °C = 2 × 400 × 100 = 80 000 J. Mass melted = 80 000/(3.3 × 105) = 8/33 kg.