Question 13
Gas LawsIn the J-tube above, Y and X are on the same horizontal level and 30 cm3 of air is trapped above Y when the atmospheric pressure is 75 cm Hg. Calculate the volume of air trapped above Y when 15 cm Hg is now poured into the limb above X.

- A.15 cm3
- B.25 cm3
- C.35 cm3
- D.45 cm3
Show the answer and explanation
Answer: B (25 cm3)
Explanation
The trapped air's pressure rises from 75 to 75 + 15 = 90 cm Hg. By Boyle's law 75 × 30 = 90 × V, so V = 25 cm3.