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JAMB Physics 1998 Question 45

Question 45

Alternating Current Circuits

In the a.c. circuit diagram above, the resonance frequency is

Diagram for this question
  1. A.5000π Hz
  2. B.2500π Hz
  3. C.5000/π Hz
  4. D.2500/π Hz
Show the answer and explanation

Answer: D (2500/π Hz)

Explanation

f0 = 1/(2π√(LC)) = 1/(2π√(8 × 10−3 × 5 × 10−6)) = 1/(2π × 2 × 10−4) = 2500/π Hz.