Question 40
Current ElectricityThe total resistance measured at PQ in the diagram above is
- A.18.0 Ω
- B.11.0 Ω
- C.4.0 Ω
- D.2.0 Ω
Show the answer and explanation
Answer: C (4.0 Ω)
Explanation
The three 2 Ω resistors in series (6 Ω) are in parallel with the 3 Ω: 6 × 3/(6 + 3) = 2 Ω. Adding the two 1 Ω resistors gives 1 + 2 + 1 = 4.0 Ω.