passwella.
Menu

JAMB Physics 1998 Question 13

Question 13

Elasticity

The tendon in a man's leg is 0.01 m long. If a force of 5 N stretches the tendon by 2.0 × 10−5 m, calculate the strain on the muscle.

  1. A.5 × 106
  2. B.5 × 102
  3. C.2 × 10−3
  4. D.2 × 10−7
Show the answer and explanation

Answer: C (2 × 10−3)

Explanation

Strain = extension ÷ original length = 2.0 × 10−5 ÷ 0.01 = 2 × 10−3.