Question 29
SoundUnder constant tension and constant mass per unit length, the note produced by a plucked string is 500 Hz when the length of the string is 0.90 m. At what length is the frequency 150 Hz?
- A.3 m
- B.4 m
- C.5 m
- D.6 m
Show the answer and explanation
Answer: A (3 m)
Explanation
Frequency is inversely proportional to length: f1L1 = f2L2. 500 × 0.90 = 150 × L, so L = 3 m.