Question 44
Electrical Energy and PowerAn electric current of 2 amperes flows in a heating coil of resistance 50 ohms for 3 minutes 20 seconds. Determine the heat produced.
- A.0.5 kJ
- B.8.0 kJ
- C.20.0 kJ
- D.40.0 kJ
Show the answer and explanation
Answer: D (40.0 kJ)
Explanation
H = I2Rt = 22 × 50 × 200 = 40 000 J = 40.0 kJ.