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JAMB Physics 1994 Question 4

Question 4

Motion

An object is projected with a velocity of 80 m s−1 at an angle of 30° to the horizontal. The maximum height reached is

  1. A.20m
  2. B.80m
  3. C.160m
  4. D.320m
Show the answer and explanation

Answer: B (80m)

Explanation

H = u2 sin2θ / 2g = 802 × (0.5)2 ÷ 20 = 1600 ÷ 20 = 80 m (g = 10 m s−2).