Question 38
Current ElectricityThe current I in the figure above is
- A.4.00A
- B.1.30A
- C.0.80A
- D.0.75A
Show the answer and explanation
Answer: A (4.00A)
Explanation
Each branch has two 2 Ω resistors in series (4 Ω); the two branches in parallel give 2 Ω. Adding the 1 Ω gives 3 Ω, so I = 12/3 = 4.00 A.