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JAMB Physics 1993 Question 12

Question 12

Equilibrium of Forces

In the diagram above, a lever of length 200m is used to lift a load of mass 180kg. The pivot at P is 20m from the load. What minimum force, F, must be applied at the end of the lever? [g = 10 m s−2]

Diagram for this question
  1. A.9 N
  2. B.18 N
  3. C.20 N
  4. D.200 N
Show the answer and explanation

Answer: D (200 N)

Explanation

Take moments about P: 180 × 10 × 20 = F × 180 (the effort is 200 − 20 = 180 m from P), so F = 200 N.