Question 39
CapacitorsThe net capacitance in the circuit shown above is
- A.8.0 μF
- B.6.0 μF
- C.4.0 μF
- D.2.0 μF
Show the answer and explanation
Answer: D (2.0 μF)
Explanation
The two 2 μF in parallel make 4 μF; in series with 4 μF: C = (4 × 4)/(4 + 4) = 2 μF.