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JAMB Physics 1990 Question 37

Question 37

Current Electricity

Three cells each of e.m.f. 1.5 V and an internal resistance of 1.0 Ω are connected in parallel across a load resistance of 2.67 Ω. Calculate the current in the load?

  1. A.0.26 A
  2. B.0.41 A
  3. C.0.50 A
  4. D.0.79 A
Show the answer and explanation

Answer: C (0.50 A)

Explanation

Identical cells in parallel give e.m.f. 1.5 V and internal resistance 1/3 Ω. I = 1.5/(2.67 + 0.33) = 0.5 A.