Question 10
ElasticityIn the figure above W1 = 200 g and W2 = 450 g. Calculate the extension of the spring per unit load. [g = 10 m s−2]

- A.6.0 × 10−5 m N−1
- B.2.5 × 10−4 m N−1
- C.6.0 × 10−3 m N−1
- D.2.5 × 10−2 m N−1
Show the answer and explanation
Answer: C (6.0 × 10−3 m N−1)
Explanation
Extension per unit load = (6.5 − 5.0) cm ÷ (4.5 − 2.0) N = 0.015 m ÷ 2.5 N = 6.0 × 10−3 m N−1. (The pointer moves down 1.5 scale divisions when the load goes from 200 g to 450 g.)