Question 46
Current ElectricityA galvanometer of resistance 20 Ω is to be provided with a shunt such that 1/10 of the whole current in a circuit passes through the galvanometer. The resistance of the shunt is
- A.2.00
- B.2.22
- C.18.00
- D.18.22
Show the answer and explanation
Answer: B (2.22)
Explanation
The shunt carries 9/10 of the current at the same p.d.: (1/10)I × 20 = (9/10)I × R, so R = 20/9 ≈ 2.22 Ω.