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JAMB Physics 1987 Question 40

Question 40

Capacitors

Two capacitances of 6 μF and 8 μF are connected in series. What additional capacitance must be connected in series with this combination to give a total of 3 μF?

  1. A.3 μF
  2. B.16 μF
  3. C.24 μF
  4. D.30 μF
Show the answer and explanation

Answer: C (24 μF)

Explanation

In series 1/C adds: 1/3 = 1/6 + 1/8 + 1/C. So 1/C = 8/24 − 4/24 − 3/24 = 1/24 and C = 24 μF.