Question 39
Current ElectricityIf Fig. 8, E is an accumulator with negligible internal resistance. If the emf is 9.0 V, then the total current is
- A.0.3 A
- B.0.8 A
- C.1.0 A
- D.1.8 A
Show the answer and explanation
Answer: C (1.0 A)
Explanation
The 5 Ω and 20 Ω in parallel give 4 Ω; with the other 5 Ω in series the total is 9 Ω. I = 9/9 = 1.0 A.