Question 15
Newton's Laws and MomentumA 1000 kg elevator is descending vertically with an acceleration of 1.0 m s−2. If the acceleration due to gravity is 10.0 m s−2, the tension in the suspending cable is
- A.1.0 N
- B.10.0 N
- C.9000.0 N
- D.11 000.0 N
Show the answer and explanation
Answer: C (9000.0 N)
Explanation
Accelerating downwards, mg − T = ma, so T = m(g − a) = 1000 × 9 = 9000 N.